sat suite question viewer

Algebra / Linear inequalities in one or two variables Difficulty: Medium

$y < - 4 x + 4$

Which point ( $x$ , $y$ ) is a solution to the given inequality in the $x y$ -plane?

Back question 18 of 73 Next

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73

Explanation

Choice D is correct. For a point $(x, y)$ to be a solution to the given inequality in the xy-plane, the value of the point’s y-coordinate must be less than the value of $- 4 x + 4$ , where $x$ is the value of the x-coordinate of the point. This is true of the point $left parenthesis negative 4 comma 0 right parenthesis$ because $0 < - 4 (- 4) + 4$ , or $0 less than 20$ . Therefore, the point $left parenthesis negative 4 comma 0 right parenthesis$ is a solution to the given inequality.

Choices A, B, and C are incorrect. None of these points are a solution to the given inequality because each point’s y-coordinate is greater than the value of $- 4 x + 4$ for the point’s x-coordinate.